2.4x^2+13x-35=0

Solution for 2.4x^2+13x-35=0 equation:

2.4x^2+13x-35=0

a = 2.4; b = 13; c = -35;
Δ = b2-4ac
Δ = 132-4·2.4·(-35)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{505}}{2*2.4}=\frac{-13-\sqrt{505}}{4.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{505}}{2*2.4}=\frac{-13+\sqrt{505}}{4.8}
$